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Changed NextTimeFromString() to NextTime()

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gorhill
2013-08-30 08:16:18 -04:00
parent c805a2ea5c
commit 22a2cb9e99
3 changed files with 7 additions and 7 deletions
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8
README.md
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@@ -82,11 +82,11 @@ Import the library:
Simplest way:
nextTime := cronexpression.NextTimeFromString("0 0 29 2 *", time.Now())
nextTime := cronexpression.NextTime("0 0 29 2 *", time.Now())
Assuming `time.Now()` is "2013-08-29 09:28:00", then `nextTime` will be "2016-02-29 00:00:00".
If you need to reuse many times a cron expression in your code, it is more efficient
If you need to reuse many times the same cron expression in your code, it is more efficient
to create a `CronExpression` object once and keep a copy of it for reuse:
cronexpr := cronexpression.NewCronExpression("0 0 29 2 *")
@@ -95,11 +95,11 @@ to create a `CronExpression` object once and keep a copy of it for reuse:
Use `cronexpression.NoMatch()` to find out whether a valid time was returned. For example,
cronexpression.NoMatch(cronexpression.NextTimeFromString("* * * * * 1980", time.Now()))
cronexpression.NoMatch(cronexpression.NextTime("* * * * * 1980", time.Now()))
will return `true`, whereas
cronexpression.NoMatch(cronexpression.NextTimeFromString("* * * * * 2050", time.Now()))
cronexpression.NoMatch(cronexpression.NextTime("* * * * * 2050", time.Now()))
will return `false` (as of 2013-08-29...)