Finish ArrayDeque.
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@ -28,6 +28,32 @@ resizing isn't too bad.
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* The analysis of add and remove didn't consider cost of resize.
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* An amortised analysis is done instead that considers the cost of all calls
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to add and remove, given a sequence of *m* calls to either.
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* Lemma: if an empty ArrayStack is created and any sequence of *m* >= 1 calls
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to add and remove are performed, the total time spent in calls to resize is
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O(m).
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* **Lemma**: if an empty ArrayStack is created and any sequence of *m* >= 1
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calls to add and remove are performed, the total time spent in calls to
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resize is O(m).
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* Optimisations (FastArrayStack): using memcpy or std::copy to copy blocks of
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data, not one element at a time.
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## ArrayQueue
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* ArrayStack is a bad implementation for a FIFO queue; either add or remove
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must work from the head with index = 0, which means all calls to that
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method will result in running time of O(n).
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* We could do this with an infinite array, using an index into the head (*j*)
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and the size of the backing array. We don't have an infinite array, so we'll
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have to use modular arithmetic with a finite stack.
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* **Theorem**: Ignoring the cost of calls to resize, an ArrayQueue supports the
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operations add and remove in O(1) per operation. Beginning with an empty
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ArrayQueue, any sequence of m add/remove operations will result in a total
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of O(m) time resizing.
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## ArrayDeque
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* Implementation of adding and removing from both ends using the same circular
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buffer technique.
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* add/remove check whether their index is before or after the halfway point and
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shift from there as a performance benefit.
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* **Theorem**: Ignoring the cost of calls to resize, an ArrayDeque supports
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set/get in time O(1) time per operation, and add/remove in O(1+min(i, n-1))
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time per operation. Beginning with an empty ArrayDeque, performing any
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sequence of m operations results in a total of O(m) time resizing.
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@ -1,3 +1,4 @@
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#include <cassert>
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#include <iostream>
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#include <ods/array.h>
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#include <ods/array_stack.h>
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@ -51,16 +52,30 @@ main(void)
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cout << "=== ArrayDeque ===" << endl;
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ArrayDeque<int> ad(1);
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for (int i = 0; i < 5; i++) {
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ad.add(0, i);
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ad.add(0, 4-i);
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}
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cout << "size: " << ad.size() << ", cap: " << ad.cap() << endl;
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for (int i = 0; i < 5; i++) {
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ad.add(ad.size() - 1, i);
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ad.add(ad.size(), i);
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}
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cout << "size: " << ad.size() << ", cap: " << ad.cap() << endl;
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for (int i = 0; i < ad.size(); i++) {
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cout << i << "\t" << ad.get(i) << endl;
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}
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auto x = ad.remove(1);
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assert(x == 1);
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x = ad.remove(7);
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assert(x == 3);
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cout << "size: " << ad.size() << ", cap: " << ad.cap() << endl;
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for (int i = 0; i < ad.size(); i++) {
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cout << i << "\t" << ad.get(i) << endl;
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}
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ad.remove(2);
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ad.remove(3);
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ad.remove(4);
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cout << "size: " << ad.size() << ", cap: " << ad.cap() << endl;
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}
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@ -55,6 +55,28 @@ public:
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n++;
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}
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T remove(int i) {
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T x = a[index(i)];
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if (i < (n/2)) {
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for (int k = i; k > 0; k--) {
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a[index(k)] = a[index(k-1)];
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}
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j = index(1);
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}
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else {
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for (int k = i; k < n-1; k++) {
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a[index(k)] = a[index(k+1)];
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}
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}
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n--;
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if (a.length > 3 * n) {
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resize();
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}
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return x;
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}
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void resize(void) {
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Array<T> b(max(2 * n, 1));
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for (int k = 0; k < n; k++) {
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